Evaluate the following product without multip | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express t

Vedclass · Accepted Answer

$8835$

Vedclass · Answer

(A) To evaluate $93 	imes 95$ without direct multiplication,we can use the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$.We can express the numbers as:$93 = 90 + 3$$95 = 90 + 5$Now,substitute these into the identity where $x = 90$,$a = 3$,and $b = 5$:$(90 + 3)(90 + 5) = (90)^2 + (3 + 5)(90) + (3 	imes 5)$Calculate each term:$(90)^2 = 8100$$(3 + 5)(90) = 8 	imes 90 = 720$$(3 	imes 5) = 15$Adding these values together:$8100 + 720 + 15 = 8835$Therefore,$93 	imes 95 = 8835$.

Evaluate the following product without multiplying directly:
$93 \times 95$

Similar Questions

Evaluate $205 \times 195$.

If $a, b, c$ are all non-zero and $a+b+c=0,$ prove that $\frac{a^{2}}{b c}+\frac{b^{2}}{c a}+\frac{c^{2}}{a b}=3$.

Factorise $: x^{3}-x^{2}-17 x-15$

Factorise the following quadratic polynomial by splitting the middle term: $12x^2 + 23x + 5$.

Factorise:
$2 \sqrt{2} a^{3} + 8 b^{3} - 27 c^{3} + 18 \sqrt{2} a b c$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Evaluate the following product without multiplying directly:$93 \times 95$